**Watching Movies at 2x solution codechef **– Chef started watching a movie that runs for a total of XX minutes.

Chef has decided to watch the first YY minutes of the movie at **twice** the usual speed as he was warned by his friends that the movie gets interesting only after the first YY minutes.

How long will Chef spend watching the movie in **total**?

**Note:** It is guaranteed that YY is **even**.

# Watching Movies at 2x solution codechef

- The first line contains two space separated integers X,YX,Y – as per the problem statement.

### Output Format

- Print in a single line, an integer denoting the total number of minutes that Chef spends in watching the movie.

### Constraints

- 1≤X,Y≤10001≤X,Y≤1000
- YY is an even integer.

## Watching Movies at 2x solution codechef

**Subtask #1 (100 points):** original constraints

### Sample Input 1

```
100 20
```

### Sample Output 1

```
90
```

### Explanation Watching Movies at 2x solution codechef

For the first Y=20Y=20 minutes, Chef watches at twice the usual speed, so the total amount of time spent to watch this portion of the movie is Y2=10Y2=10 minutes.

For the remaining X−Y=80X−Y=80 minutes, Chef watches at the usual speed, so it takes him 8080 minutes to watch the remaining portion of the movie.

In total, Chef spends 10+80=9010+80=90 minutes watching the entire movie.

### Sample Input 2

```
50 24
```

### Watching Movies at 2x solution codechef

```
38
```

### Explanation

For the first Y=24Y=24 minutes, Chef watches at twice the usual speed, so the total amount of time spent to watch this portion of the movie is Y2=12Y2=12 minutes.

For the remaining X−Y=26X−Y=26 minutes, Chef watches at the usual speed, so it takes him 2626 minutes to watch the remaining portion of the movie.

In total, Chef spends 12+26=3812+26=38 minutes watching the entire movie.