# [Solution] Minimum Average Difference solution leetcode

Minimum Average Difference solution leetcode – You are given a 0-indexed integer array `nums` of length `n`.

The average difference of the index `i` is the absolute difference between the average of the first `i + 1` elements of `nums` and the average of the last `n - i - 1` elements. Both averages should be rounded down to the nearest integer.

## [Solution] Minimum Average Difference solution leetcode

Return the index with the minimum average difference. If there are multiple such indices, return the smallest one.

Note:

• The absolute difference of two numbers is the absolute value of their difference.
• The average of `n` elements is the sum of the `n` elements divided (integer division) by `n`.
• The average of `0` elements is considered to be `0`.

## [Solution] Minimum Average Difference solution leetcode

```Input: nums = [2,5,3,9,5,3]
Output: 3
Explanation:
- The average difference of index 0 is: |2 / 1 - (5 + 3 + 9 + 5 + 3) / 5| = |2 / 1 - 25 / 5| = |2 - 5| = 3.
- The average difference of index 1 is: |(2 + 5) / 2 - (3 + 9 + 5 + 3) / 4| = |7 / 2 - 20 / 4| = |3 - 5| = 2.
- The average difference of index 2 is: |(2 + 5 + 3) / 3 - (9 + 5 + 3) / 3| = |10 / 3 - 17 / 3| = |3 - 5| = 2.
- The average difference of index 3 is: |(2 + 5 + 3 + 9) / 4 - (5 + 3) / 2| = |19 / 4 - 8 / 2| = |4 - 4| = 0.
- The average difference of index 4 is: |(2 + 5 + 3 + 9 + 5) / 5 - 3 / 1| = |24 / 5 - 3 / 1| = |4 - 3| = 1.
- The average difference of index 5 is: |(2 + 5 + 3 + 9 + 5 + 3) / 6 - 0| = |27 / 6 - 0| = |4 - 0| = 4.
The average difference of index 3 is the minimum average difference so return 3.
```

Example 2:

```Input: nums = [0]
Output: 0
Explanation:
The only index is 0 so return 0.
The average difference of index 0 is: |0 / 1 - 0| = |0 - 0| = 0.
```

## Minimum Average Difference solution leetcode

• `1 <= nums.length <= 105`
• `0 <= nums[i] <= 105`