Table of Contents

## [Solution] Check Distances Between Same Letters solution leetcode

**Check Distances Between Same Letters solution leetcode** – You are given a **0-indexed** string `s`

consisting of only lowercase English letters, where each letter in `s`

appears **exactly** **twice**. You are also given a **0-indexed** integer array `distance`

of length `26`

.

Each letter in the alphabet is numbered from `0`

to `25`

(i.e. `'a' -> 0`

, `'b' -> 1`

, `'c' -> 2`

, … , `'z' -> 25`

).

In a **well-spaced** string, the number of letters between the two occurrences of the `i`

letter is ^{th}`distance[i]`

. If the `i`

letter does not appear in ^{th}`s`

, then `distance[i]`

can be **ignored**.

Return `true`

* if *`s`

* is a well-spaced string, otherwise return *

`false`

.

## [Solution] Check Distances Between Same Letters solution leetcode

Input:s = "abaccb", distance = [1,3,0,5,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Output:trueExplanation:- 'a' appears at indices 0 and 2 so it satisfies distance[0] = 1. - 'b' appears at indices 1 and 5 so it satisfies distance[1] = 3. - 'c' appears at indices 3 and 4 so it satisfies distance[2] = 0. Note that distance[3] = 5, but since 'd' does not appear in s, it can be ignored. Return true because s is a well-spaced string.

## [Solution] Check Distances Between Same Letters solution leetcode

Input:s = "aa", distance = [1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0]Output:falseExplanation:- 'a' appears at indices 0 and 1 so there are zero letters between them. Because distance[0] = 1, s is not a well-spaced string.

## [Solution] Check Distances Between Same Letters solution leetcode

`2 <= s.length <= 52`

`s`

consists only of lowercase English letters.- Each letter appears in
`s`

exactly twice. `distance.length == 26`

`0 <= distance[i] <= 50`